# How do you solve #log(x+1) - log(x-1)=1#?

##### 2 Answers

Use the law

#log(a) - log(b) = log(a/b)# .

Hence

#log((x+ 1)/(x- 1)) = 1#

#(x + 1)/(x - 1) = 10#

#x +1 = 10(x - 1)#

#x + 1 = 10x - 10#

#11 = 9x#

#x = 11/9#

We now verify that it satisfies the equation. It will as long as

Hopefully this helps!

The solution is

#### Explanation:

Use these

Now here's the actual problem:

That's the solution. Hope this helped!